Amother who is 40 years old has a daughter and a son. the son is twice as old as the daughter. in 15 years the sum of all their ages will be 100 years. how old are the siblings now?

15 and 5

Step-by-step explanation:

Mother's current age:  40

daughter's age:  d

son's age:  s

son is 2x as old as daughter:  s = 2d

Then, 15 years from now, the sum of their ages will be:

(40 + 15) + (2d + 15) + (d + 15) = 100

or

55 + 15 + 15 + 3d = 100

85 + 3d = 100, or 3d = 15, or d = 5.

Then the son's age is 3(5) = 15 and the daughter's is 5.

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3