Plz
in △abc m∠cab = 40° and m∠abc = 60°. circle, going through points a and c, intersects sides ab and bc in points d and e respectively. find all angles in quadrilateral aced.

m∠A=40°, m∠C=80°, m∠E=140°, m∠D=100°.

Step-by-step explanation:

Quadrilateral ACED is inscribed into the circle (see attached diagram).

Inscribed Quadrilateral Theorem: A quadrilateral can be inscribed in a circle if and only if the opposite angles are supplementary (add up to 180°).

Since angle CAB has the measure of 40°, then opposite quadrilateral's angle CED has the measure of

180°-40°=140°.

Since angle ABC has the measure of 60°, then the third triangle's angle BCA has the measure

180°-40°-60°=80°.

Since angle BCA has the measure of 80°, then opposite quadrilateral's angle ADE has the measure of

180°-80°=100°.

So, in quadrilateral ACED,

m∠A=40°, m∠C=80°, m∠E=140°, m∠D=100°.

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..

your answer is a

step-by-step explanation:

4*4*4*4=256