What quadratic has roots x=8 and x= -5
x^2+3x-40
x squared minus 3x -40
x squared +13 x +40
x squared -13 x +40

So the correct option is X squared -3 X +40

Step-by-step explanation:

If a polynomial has roots x=8 and x=-5, then we know that the factorized form is:

(x-8)(x+5)

So, to find the polynomial we need to expand the polynomials:

(x-8)(x+5) = (x^2 +5x - 8x + 40) = x^2 -3x + 40

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.