The slop-intercept form of the equation of a line that passes through points (-2,-13) is y=5x-3 what is the point slope form of the equation of the equation for this line

y + 13 = 5(x + 2)

Step-by-step explanation:

y=5x-3 what is the point slope form of this equation?

The point-slope form looks like y - k = m(x - h), where (h, k) is the given point and m is the given slope.

Here the given point is (-2, -13).  Therefore, the desired equation is:

y -(-13) = 5( x - [-2] ), or

y + 13 = 5(x + 2)

Step-by-step explanation:

The given function passes through (-2,-13).

The slope-intercept form of this equation is .

This implies that; the slope of the given function is;

The point-slope form of this function is given by the formula;

We have

We substitute the point and the slope into the function to obtain;

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.