If x-3 and x+3 are the factors of 4x^3+ax^2+bx . find value of a and b

a=0 , b=-36

Step-by-step explanation:

factors (x-3) (x+3)

means x=3 , -3

so u then substitute it in the equation and one by one

when u do that you'll get  81a+3b=-108 (1)

                                             81a-3b=108 (2)

then u solve them simultaneously, by doing that,

u get  a=0 then b=-36

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step-by-step explanation: