What is the equation of a line that passes through point (6, 3) and is perpendicular to a line with a slope of -3/2?

For this case we have that by definition, the slope point equation of a line is given by:

Where:

m: It's the slope

b: It is the cutoff point with the y axis

By definition, if two lines are perpendicular, the product of their slopes is -1. That is to say:

Substituting:

We substitute the point to find "b":

Finally:

d. vertex

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.