Write the following parametric equations as a rectangular equation by
eliminating the parameter.

x=6-t

y= 3t-4

show all work.

3x + y = 12

Step-by-step explanation:

x = 6 - t

y = 3t - 4

We have to convert these equations in rectangular form which means that we have to express them in terms of x and y only. For this we have to eliminate "t".

From first equation we get the value of t as:

x + t = 6

t = 6 - x

Using this value in second equation, we get:

y = 3(6 - x) - 4

y = 18 - 3x - 12

3x + y = 6

This is the equation in rectangular form.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752