Asquare has an area of 64 square units. which set of coordinates could be the vertices of the square?
a) (3, –35) and (3, –28)
b) (21, –14) and (21, –22)
c) (32, –42) and (32, –7)
d) (74, 19) and (82, 27)

B

Step-by-step explanation:

it is 64 units so 8 units long each

B) (21, -14) and (21, -22)

Step-by-step explanation:

Given,

The area of the square = 64 square unit,

Let x be the side of the square,

Hence, the side of the square = 8 unit,

⇒ The distance between the adjacent vertices in the square = 8 units,

By the distance formula,

The distance between (3, -35) and (3, -28) is,

Thus, (3, -35) and (3, -28) can not be the vertices of the square.

The distance between (21, -14) and (21, -22) is,

Thus, (21, -14) and (21, -22) are the vertices of the square.

The distance between (32, -42) and (32, -7)  is,

Thus, (32, -42) and (32, -7)  can not be the vertices of the square.

The distance between  (74, 19) and (82, 27) is,

Thus, (74, 19) and (82, 27) can not be the vertices of the square.

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90

step-by-step explanation:

*calories burned = (weight)(calorie factor)*

calories burned = 180 (0.65)

calories burned = 117

the calories he used up is 117, which is 65% of his weight.