What is the value of the expression [36-9+(8x6)-21]divided by 3

12-3+(2.7x2)-7

Step-by-step explanation:

you would have to divide each number in the equation by 3 which would look like this:

36 / 3 = 12

-9 / 3 = -3

8 / 3 = 2.6666 repeating, which would be rounded up to 2.7

6 / 3 = 2

-21 / 3 = -7

i hope this helps :)

18

Step-by-step explanation:

using Pemdas

you would do the parentheses first

in the parentheses theres parentheses so 8*6 is 48

then do the rest of the parentheses so 36-9+48-21 which equals 54

then lastly divide by 3

which equals 18

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

i don't know, but that looks pretty bad. my school passed us unless we failed in all the subjects, but idk abt ur school's rules.

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