You are given the system of equations to solve by the elimination method, which is an incorrect step that will not produce a system with the same solution?

2x + y = −10
3x + 4y = −20

a) multiply the first equation by 4 and subtract the second equation
b) multiply the first equation by −4 and add the second equation
c) add 8 times the first equation and −2 times the second equation
d) multiply y by 4 in the first equation and subtract the second equation

Option D) multiply y by 4 in the first equation and subtract the second equation

Step-by-step explanation:

we have

2x+y=-10 > first equation

3x+4y=-20 ---> second equation

Verify each case

case A) multiply the first equation by 4 and subtract the second equation

so

(2x+y)*4=-10*4 > 8x+4y=-40

[8x+4y=-40]-[3x+4y=-20] > 5x=-20 > x=-4

This step is correct

case B) multiply the first equation by -4 and add the second equation

so

(2x+y)*-4=-10*-4 > -8x-4y=40

[-8x-4y=40]+[3x+4y=-20] >-5x=20 > x=-4

This step is correct

case C)  add 8 times the first equation and −2 times the second equation

so

(2x+y)*8=-10*8 > 16x+8y=-80

(3x+4y)*-2=-20*-2 > -6x-8y=40

[16x+8y=-80]+[-6x-8y=40] >10x=-40 > x=-4

This step is correct

case D) multiply y by 4 in the first equation and subtract the second equation

so

2x+4y=-10

[2x+4y=-10]-[3x+4y=-20] > -x=-10+20 > x=-10

This step is incorrect

NOT produce a system with the same solution

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1