Kevin recorded the ages of the next 12 people who entered his grocery store. he asked his brother john to find the mean, median, and the mode of the data set: [ 6,18,8,4,18,20,10,10,21,6,17,18]. john's results are shown. mean =156/12=13. median = 20+10/2=15, mode=10. i'll post a picture of the questions.

Step-by-step explanation:

6,18,8,4,18,20,10,10,21,6,17,18

Arrange the data in ascending order

4,6,6,8,10,10,17,18,18,18,20,21

Part A

Mean = 156/12 = 13 is correct

Median = 15 is incorrect because the data is not arranged. Median when there are even numbers will be: 10+17/2 = 13.5

Mode = 10 is incorrect, because mode is most repeating value and in the data set it is 18 so, Mode = 18

Part B

10,12 and 52 should be added in data set in ascending order

4,6,6,8,10,10,10,12,17,18,18,18,20,21,52

Mean = 230/15 = 15

Median = Middle term as odd numbers = 8th term = 12

Mode = 10 and 18

Part C

Both median and mean are used to measure central tendency.

The best measure of central tendency is considered median because the mean is affected by the presence of outliers while median is not affected by outliers.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,