Which of the points a(−6, 2), b(0, 0), c(4, −2), d(−12, 6), e(−10, 10) belong to the graph of direct variation y=− 1 2 x?

ANSWER

B(0, 0),

EXPLANATION

The given points are A(−6, 2), B(0, 0), C(4, −2), D(−12, 6), E(−10, 10).

The equation of the direction variation is

The point that belongs the graph of the direct variation must satisfy the variation equation.

Note that the graph of direct variation equation passes through the origin therefore the point (0,0) satisfies it.

0=-12(0)

0=0

This is true

The other points do not satisfy this variation equation, hence they do not lie on its graph

9

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.