What is the coordinates of the vertex of y+10=4(x-1)^2

(1, -10)

Step-by-step explanation:

Only the y can be on the left hand side. The square has been completed so all you need do is transfer the 10 to the right and read the x,y values for the vertex.

I have provided a graph to show you that the vertex and my answer are the same (hopefully).

y + 10 = 4(x - 1)^2          Subtract 10 from both sides.

y + 10-10=4(x -1)^2 -10  Combine

y = 4(x - 1)^2 - 10

Now we need to make the square term = 0

x - 1  = 0                        Add 1 to both sides

x - 1 + 1 = 0 +1               Combine

x = 1                              When x = 1 the square term will equal 0.

The vertex should be (1, - 10)

what level of math? also i don't need to be paid if i can you.