Me ! i'm dying and failing math just awnser this

1.
in another project, researchers caught and tagged 85 sea lions in a bay. later they caught and released 50 sea lions. of those, 9 had tags. estimate the sea lion population in the bay.

about 194 sea lions

about 153 sea lions

about 529 sea lions

about 472 sea lions

2.

the table shows the results of a biologist who captures and tags lake trout, and then sets them free. what is the trout population in the lake?

about 90

about 340

about 130

about 250

3.
a park ranger tags 100 animals. use a proportion to estimate the total population for the sample.

83 out of 125 animals are tagged

95 animals

67 animals

142 animals

151 animals

4.

use the table. estimate the total deer population for year 8.

about 1,815 deer

about 2,467 deer

about 1,934 deer

about 2,081 deer

5.
the total number of ducks in a zoo is known to be 4,109. of these 4,109 ducks, 960 have been marked. if you catch 1,100 of these ducks, how many would you expect to be marked?

143

257

225

189

We can set up a proportion to solve this.  9 lions were tagged out of a sample of 50.  This gives us the ratio 9/50 for the first part of the proportion.

For the second ratio, we know 85 lions were tagged out of an unknown population; this gives us 85/x.

Our proportion is

9/50 = 85/x

Cross multiply:

9*x = 50*85

9x = 4250

Divide both sides by 9:

9x/9 = 4250/9

x = 472.222 

To the nearest whole number, this is 472 sea lions.

Step-by-step explanation:

We can set up a proportion to solve this.  9 lions were tagged out of a sample of 50.  This gives us the ratio 9/50 for the first part of the proportion.

For the second ratio, we know 85 lions were tagged out of an unknown population; this gives us 85/x.

Our proportion is

9/50 = 85/x

Cross multiply:

9*x = 50*85

9x = 4250

Divide both sides by 9:

9x/9 = 4250/9

x = 472.222 

To the nearest whole number, this is 472 sea lions.

c. 1,233 miles

(a) {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …}

(b) $59 398

step-by-step explanation:

(a) the annual sequence of profits

aₙ = a₁rⁿ⁻¹

the model for the sequence of profits is {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …} .

(b) profit after 15 yr

  a₁ = $ 30 000

  r = 1.05

a₁₅ = 30 000 × 1.05¹⁴

a₁₅ = 30 000 × 1.979 93

a₁₅ = $59 398

the profit in year 15 will be $59 398.