Find the midpoint of (7,-5) and (-1,-2)

For x = 7 + (-1) = 6 -> 6/2 = 3

For y = -5 + (-2) = -7 -> -7/2 = -3.5

Midpoint(3, 3.5)

For x = 7 + (-1) = 6 -> 6/2 = 3

For y = -5 + (-2) = -7 -> -7/2 = -3.5

Midpoint(3, 3.5)

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

i think the answer would be c