Abox has a base of 12 inches by 12 inches and a height of 30 inches. what is the length of the interior diagonal of the box? round to the nearest hundredth. enter your answer in the box.

The sides of the box are 12in by 12in by 30in.

The interior diagonal =[12^2+12^2+30^2]0.5

=[144+144+900]^0.5

=1188^0.5

The final answer is 34.47in.

My deepest apology if this is not what you meant.

= 34.47in.

step-by-step explanation: i dont

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length