Which of these ordered pairs is a solution to this inequality? y > 3x+2

hello :  (2 ; 9)

Step-by-step explanation:

y > 3x+2(1)

put : x and y in : (1)

1) for : (-2 ; -7)   where x = - 2  and y = -7  so :-7 > 3(-2)+2

-7 > - 4   false

2) for : (-1 ; -5)   where x = - 1  and y = -5  so :-5> 3(-1)+2

-5 >  -1   false

3) for : (2 ; 8)   where x =  2  and y = 8  so :8 > 3(2)+2

8 > 8   false

4) for : (2 ; 9)   where x =  2  and y = 9  so :9 > 3(2)+2

9 > 8   true

the ordered pairs is a solution to this inequality  y > 3x+2 :  (2 ; 9)

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.

0lz try yourself sorry for not answering