What is the best approximation of the projection of (5, -1) onto (2, 6)

0.1(2, 6) = (0.2, 0.6)

Step-by-step explanation:

The projection of B onto A will be ...

|B|·cos(θ)×uA

where uA = A/|A|, a unit vector in the A direction.

The dot product of A and B is ...

A•B = |A|·|B|·cos(θ), so the desired vector is ...

projection of B onto A = (A•B)/|A|·(A/|A|) = A·(A•B)/|A|²

For A = (2,6) and B = (5, -1), this is ...

projection of (5, -1) onto (2, 6) = (2, 6)·(2·5-6·1)/(2²+6²) = (2, 6)·4/40 = 0.1·(2, 6)

= (0.2, 0.6)

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

the total estimated nappy use.=10,500,000

step-by-step explanation:

given that on an average the average baby uses 3528 napkins.

in a particular year 2014, the number of births were 299697 in new south wales.

rounding off the number of births to the nearest hundred thousand we have

no of birtsh = 300000

also rounding off the average usage to nearst thousand we get

average use of a baby = 3500

hence total number of nappy estimated to be used = 3500x300000

= 10,500,000

answer is 10,500,000 nappies