2. find the lateral area of the pyramid to the nearest whole number.
a) 200 m^2
b) 204 m^2
c) 208 m^2
d) 212 m^2

area of lateral surface

Area=0.5bh×4(because there are four lateral faces)

b=12m

Area=0.5×12m×h

Area=6m×h

using Pythagoras theorem to find height of the triangle of lateral surface.

h²=6²+H²(height of the pyramid)

h²=6²+6²

h²=36+36

h²=72

h=root of 72

h=8.5cm(rounded to nearest tenth)

SA=6m×8.5m×4

Sa=51m²×4

Sa=201m²

answer.. 204m²