How i can factor to solve the equation

2x^3+3x^2-11x-6=0

(x-3)(2x^2+3x-2)=0

(x-3)((2x-1)(x+2))=0

(x-3)(2x-1)(x+2)=0

x=3,1/2,-2

Use my steps to answer remember for a question like that use

( 2x³ +3x²)-( 11x-6 )= 0

Step-by-step explanation:

So far you have solved linear equations, which include constant terms—plain numbers—and terms with the variable raised to the first power,  

x1=xx^1=xx  1 =5 x

, start superscript, 1, end superscript, equals, x

You may have also solved some quadratic equations, which include the variable raised to the second power, by taking the square root from both sides.

Here is example

(x−1)    x−1=0  x=1  (x+3)=0  x+3=0 x=−3

Substituting either  x=1x=1 x=1 x, equals, 1  or  x=−3x=-3 x=−3 x, equals, minus, 3  into the equation will result in the true statement  0=00=0 0=0 0, equals, 0 , so they are both solutions to the equation.

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,

if im not mistaking its

step-by-step explanation: