Select all that apply. if 2x^2-6x=0 then

Since part of the question is not given, i assume u wanna find the possible values of x. If so, the answers are 0 and 3.

Step-by-step explanation:

2x^2 - 6x = 0

Note that 2 is a common factor. Since 0/2 = 0, we can divide both sides by 2.

Then,

x^2 - 3x    = 0

We take the common factor, aka x out.

Then we get,

x(x-3)  = 0

So one of x or x-3 has to equal 0.

If x -3 = 0, x is 3, and if x is 0, x is obviously = 0.

So x could be 3 or 0.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

5

step-by-step explanation: