Which function can be used to find the number of cells of bacteria in the population at time t

db / dt = kb  

this becomes b(t) = Ce^(kt)  

C = 100, the initial population  

P(1) = 420 = 100 e^(1k)  

4.2 = e^k  

ln 4.2 = k  

a) thus, b(t) = 100 e^(t ln 4.2)  

b) b(3) = 100 e^(3 ln 4.2)  

c) growth constant will still be ln 4.2 (constant percentage of populatioin)  

d) 10000 = 100 e^(t ln 4.2)  

100 = e^(t ln 4.2)  

ln 100 = t ln 4.2  

t = ln 100 / ln 4.2

Step-by-step explanation:

the answer is c just got it on ed

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.