What is the length of the hypotenuse of this triangle? round to the nearest tenth

√29 or 5.4

Step-by-step explanation:

Given in the question a right angle triangle

height of right angle triangle = 5

base of right angle triangle = 2

hypotenuse of right angle triangle = x

We will use pythagorus theorem

hypotenuse² = base² + height²

x² = 5² + 2²

x² = 25 + 4

x² = 29

x = √29

x = 5.4

The length of the hypotenuse of this triangle is 5.4

Step-by-step explanation:

For a given Triangle

Let the Triangle ABC

m∠B = 90°, AB = 5, BC = 2, AC = ?

Now, By Pythagoras Theorem

AC² = AB² + BC²

AC² = (5)² + (2)²

AC² = 25 + 4

AC² = 29

AC = √29 = 5.4

Thus, The length of the hypotenuse of this triangle is 5.4

-TheUnknownScientist

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: