Abox contains 4 white balls and 6 yellow balls. a ball is drawn randomly from the box and is not replaced. what is the probability that both balls are white? a.) 3/25 b.) 8/45 c.) 2/15 d.) 4/25

C

Step-by-step explanation:

The question is actually, 2 balls are randomly taken and not replaced. What is the probability that both balls are white?

There are 4 while balls and 6 yellow balls. So total 10 balls.

The probability of a white ball at first draw is 4/10

** Since not replaced, so we have 1 less white ball and 1 less total ball. So there are now 3 white balls and 9 total balls.So:

The probability of a white ball at second draw is 3/9

We multiply both so: 4/10 * 3/9 = 2/15

Correct answer is C

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]