Charles needs to fill a large fish tank with water using a hose. he has two hoses from which to choose. water flows through each hose at a constant rate. the graph below shows the amount of water, in gallons , that flows through holes a based on the number of minutes used. a total of 110 gallo s of water can flow through hose b in 10 minutes. which hose has a faster water rate, in gallons per minute, and what is that rate?

 Hose b has a faster water flow rate.

 HOSE B

since it said that a total of 110 gallons of water can flow through hose b in 10 minutes you divide 110 by 10 to get the amount of water that flows through hose b in gallons in one minute.

110/10=11

y=11 x

so,it means 11 gallons of water flows through hose b in 1 minute.

HOSE A

you can chose two points from the graph to get the rate of change,and then you can subtract y2 from y1 and x2 from x1.

Points from the graph: (2,12) , (4,24)

(x1,y1)=(2,12)

(x2,y2)=(4,24)

Now you subtract 24 from 12 and 2 from 4

M=y2-y1 / x2-x1= 24-12/2-4=12/2=6

and you just divide 12/2 which is 6,which means that in hose a a total of 6 gallons of water flows in one minute.

so the equation for hose a is y=6 x

So hose b has a faster water flow rate since y=6 x < y=11 x.

what graph

step-by-step explanation:

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x