In a competition between players x and y, the first player to win three games in a row or a total of four games wins. how many ways can the competition be played if x wins the first game and y wins the second and third games?

  7 ways (y wins 4 of them)

Step-by-step explanation:

Possibilities are ...

{x, y, y, y} — y wins

{x, y, y, x, x, x} — x wins

{x, y, y, x, y, y} — y wins

{x, y, y, x, x, y, x} — x wins

{x, y, y, x, x, y, y} — y wins

{x, y, y, x, y, x, x} — x wins

{x, y, y, x, y, x, y} — y wins

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.