Suraj took a slice of pizza from the freezer and put it in the oven. the pizza was heated at a constant rate.
the table compares the pizza's temperature (in degrees celsius) and the time since suraj started heating it (in minutes).
time (minutes) temperature (degrees celsius)
111 2.52.52, point, 5
777 47.547.547, point, 5
131313 92.592.592, point, 5
how fast was the pizza heated?

degrees celsius per minute

The pizza heats up an average of 7.50 degrees per minute

Step-by-step explanation:

The table shown

Time (minutes)Temperature (degrees Celsius)

1                          2.52

7                          47.547

13                          92.592

Since the pizza was heated at a constant rate, we can model the experiment as a line, where the slope represents how fast the pizza was heated

Slope

m   =  (y2 - y1)/(x2 - x1)

Let

(x1,y1) = (7, 47.547)

(x2,y2) = (13, 92.592)

m = (92.592 - 47.547)/(13-7)

m = 7.5075

The pizza heats up an average of 7.50 degrees per minute

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29