Express the seventh root of unity in standard form a+bi

Just remember , when the power of the complex is more than 4, divide by 4 and consider the remainder.

Now , we know

i^0=1

i^1=i

i^2= -1

i^3= -i

Know, take 7

7%4=3(I’m trying to say that the remainder is 3. The expression I used is used in computer science don’t use it in maths xD )

So (a+ib)^7=(a+ib)^3

Expand this using (x+y)^3=x^3+y^3+ 3xy^2+3yx^2

Solving this, you get, (a+ib)^7= a^3-ib^3+ 3iba^2+3ab^2

step-by-step explanation:

i think you should think about the question and not look online.

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled