What is the slope of the line passing through the points (4,8) and (1,6)

a.-3/2
b.3/2
c.2/3
d.-2/3

The answer would be c. 2/3

Step-by-step explanation:

How you find it

Use the equation

y2-y1 / x2-x1 to find a slope with 2 points

So what I did was 6-8=-2 and 1-4=-3

They are both negatives so they become positive

Hope this helped

*(/)Befri.stends(/)

sec ф = 5/3 (quadrant 4)

let x = base

y = perp

z = hypotenuse

sec ф = hypotenuse/base = 5/3

⇒ z = 5 and x = 3

finding y:

z² = x² + y²

5² = 3² + y²

y² = 25-9

y² = 16

y = 4

now finding all other geometric functions of theta:

sin ф = y/z = 4/5

sin ф = -4/5 (sin is negative in the 4th quadrant)

cos ф = x/z = 3/5

cos ф = 3/5 (cos is positive in 4th quadrant)

tan ф = y/x = 4/3

tan ф = -4/3 (tan is negative in 4th quadrant)

cosec ф = z/y = 5/4

cosec ф = -5/4 (cosec is negative in the 4th quadrant)

cot ф = x/y = 3/4

tan ф = -3/4 (tan is negative in 4th quadrant)

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