Which points are solutions to the linear inequality y < 0.5x + 2? check all that apply. (–3, –2) (–2, 1) (–1, –2) (–1, 2) (1, –2) (1, 2)

Check all points for being the solutions of inequality :

1. For point (–3, –2) you have that x=-3 and y=-2, then

- true.

2. For point (–2, 1) you have that x=-2 and y=1, then

- false.

3. For point (–1, –2) you have that x=-1 and y=-2, then

- true.

4. For point (–1, 2) you have that x=-1 and y=2, then

- false.

5. For point (1, –2) you have that x=1 and y=-2, then

- true.

6. For point (1, 2) you have that x=1 and y=2, then

- true.

points (–3, –2), (–1, –2), (1, –2), (1, 2) apply.

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.