Carlos needs to paint the outside of the shed in his backyard, including its roof but not including its floor.
what is the total area of the surfaces that he needs to paint?

Step-by-step explanation:

we know that

The total area of the surfaces that he needs to paint is equal to the lateral area of the rectangular prism plus the area of the two triangular faces and two square faces of the root.

so

Step-by-step explanation:

Given : Carlos needs to paint the outside of the shed in his backyard, including its roof but not including its floor.

To Find: What is the total area of the surfaces that he needs to paint?

Solution:

Length of backyard= 8 feet

Breadth of backyard = 5 feet

Height of backyard = 6 feet

So, Area of walls of backyard = Lateral surface area =

                                                                                      =  

                                                                                      =  

Area of two triangular faces of roof =

Base of triangular face = 8 feet

Height of triangular face = 3 feet

So, Area of two triangular faces of roof =

                                                                  =

Area of two square roof =

Side of square = 5 feet

So, Area of two square roof =

                                               =

So, total area to be painted =  

                                             =  

Hence the total area of the surfaces that he needs to paint is  

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;