If two quadrilaterals are congruent, then there must be how many pairs of corresponding sides

If two quadrilaterals are congruent, then there must be four pairs of corresponding sides.

Step-by-step explanation:

We know that if two polygons are congruent then their corresponding sides and angles are congruent .

Such that for any two polygons having 'n' sides are congruent, then there must be 'n' pairs of corresponding sides.

Therefore,  if two quadrilaterals are congruent, then there must be four pairs of corresponding sides.

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°