10 points & brainliest - what are the coordinates of vertex j of the pre-image?

ANSWER

(0,-4)

EXPLANATION

The coordinates of J' are (0,-2).

Let the coordinates of J be (a,b).

Then we apply the rule of the dilation to get,

.

This implies that,

And also,

Hence the vertex J of the preimage is

(0,-4)

The first choice is correct.

(0, -4)

Step-by-step explanation:

A dilation rule of means that the coordinates of each point in the pre-image must be divided by 2.

So, we must multiply the coordinates of each point in the image by 2 to get back to the pre-image.

The coordinates of vertex J' are (0, -2), so those of J must have been (0, -4).

Vertex J moved to the origin along the ray until its coordinates were halved.

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

what chart am i supposed to follow?