In a certain algebra 2 class of 26 students, 18 of them play basketball and 5 of them play baseball. there are 6 students who play neither sport. what is the probability that a student chosen randomly from the class plays basketball or baseball?

3/26 students or 11%

Step-by-step explanation:

probability dependant formula:P(A∪B)=P(A)+P(B)−P(A∩B)

P(a)= basketball

P(b)=baseball

so

P(AUB)=P(A)+P(B)-P(A∩B)= 18/26+5/26-20/26=3/26

3/26 or 11%  

OR you could solve this by adding all the sport/non sport #'s 18+5+6=29 and subtract 26 from 29

29-26=3

hence 3/26 students would randomly play basketball or baseball

Hope this Helps!

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