What is the smallest number of chickens that can walk in this formation: two chickens in front of a chicken; two chickens behind a chicken, and a chicken between two chickens?

smallest number of chickens= 3

Step-by-step explanation:

In this question the given formation is:

two chickens in front of a chicken

the total number of chickens are 3

two chickens behind a chicken

the total number of chickens are 3

a chicken between two chickens

the total number of chickens are 3

So, the smallest number of chicken that can be required to make this formation will be 3.

So, if we consider that the chickens are walking in a straight line, two (2nd and 3rd) chickens will be behind the 1st chicken, two chickens( 1st and 2nd) will be in front of the last (3rd) chicken and one (2nd) chicken is in the middle of two (between 1st and 3rd) chicken.

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column

what is the model?

step-by-step explanation: