What is the equation of line that passes through the point (6,-6) and has a slope of -5over 3

the equation is : y = (-5/3)x+4

Step-by-step explanation:

Hello:

equation is the line is : y = ax+b        a is a slope

y = (-5/3)x+b

passing through the point (6;-6) : -6 =(-5/3)(6)+b   so : b = 4

y = (-5/3)x+4

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

step-by-step explanation:

what grade level is this? need to know so i can look in my old textbooks!