Is the sequence 5, 9, 15, an arithmetic sequence? explain.

Not an Arithmetic Sequence

Step-by-step explanation:

In an Arithmetic Sequence the difference between two consecutive terms of the sequence is always the same. This difference is known as common difference of the Arithmetic Sequence and is denoted by d

So, in order to check if any given sequence is Arithmetic Sequence or not, juts find the difference of the consecutive terms. If the difference is the same, the given sequence will be Arithmetic Sequence.

Difference of 1st and 2nd term of given sequence = 9 - 5 = 4

Difference of 2nd and 3rd term of given sequence = 15 - 9 = 6

Since these differences are not the same, the given Sequence is not an Arithmetic Sequence.

It is not an arithmetic sequence.

Step-by-step explanation:

We are given the following sequence and we are to determine and explain if it is an arithmetic sequence.

For a sequence to be arithmetic, there is a constant difference between two consecutive terms which is known as the 'common difference'.

Here, the difference between the consecutive terms is not constant in the given sequence. Therefore, it is not an arithmetic sequence.

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3