Five years ago janeta age was one_fifth of her mother'sage .now she is one_third of her mother's age. find their present ages?

J - Janeta's age  M - mother's age

A) (J-5) = .2 * (M-5)

B) J = (1/3) * M

Subtracting 5 from both sides of B:

B) J -5 = (1/3)M -5

then we substitute the right side of this into the left side of A and we get

(1/3)M -5 = .2 M -1

.333333333333M -5 = .2M -1

.1111111111111111111M = 4

Mother's Age = 36

Janeta's Age = 12

Step-by-step explanation:

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step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl