In triangle abc, b=17 55', c=98 15' and a=17. what is the length of c?
a. 26.2
b. 14.3
c. 22.4
d. 18.7

Option d. 18.7 units

Step-by-step explanation:

step 1

we have

B=17° 55'=17+55/60=17.92°

C=98° 15'=98+15/60=98.25°

step 2

Find the measure of angle A

∠A+∠B+∠C=180°

substitute

∠A+17.92°+98.25°=180°

∠A=180°-(17.92°+98.25°)=63.83°

step 3

Applying the law of sines

c/sin(C)=a/sin(A)

substitute the values

c/sin(98.25°)=17/sin(63.83°)

c=sin(98.25°)*17/sin(63.83°)

c=18.7 units