Write the quadratic equation y= (x)2-6x-7 in vertex form

y = (x-3)^2 -16

Step-by-step explanation:

y = x^2 -6x-7

We need to complete the square

b= -6

b/2 = -6/2 = -3

(b/2) ^2 = (-3)^2 =9

Add 9 then subtract 9 to balance the equation

y = x^2 -6x +9 -9 -7

y = (x^2 -6x+9) -16

The terms in parentheses is (x-b/2)^2

y = (x-3)^2 -16

This is in vertex form

The vertex is (3,-16)

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

can you rephrase the question ? it is unclear : -)

step-by-step explanation: