Write an equation to solve each problem and then solve it. b in a 3-digit number, the hundreds digit is four more than the ones digit and the tens digit is twice the hundreds digit. if the sum of the digits is 12, find the three digits. find the number.

digits are: 0, 4, 8. The required number is: 480.

Step-by-step explanation:

→ Let ones digits is 'x', then according to the condition the hundreds digit is 'x+4', and the tens digit is '2(x+4)'.

→ According to the condition the sum of the digits is: x+(x+4)+2(x+4)=12.

→ After evaluation this equation, x=0 - this is ones digit;

→ x+4=0+4=4 - this is hundreds digit;

→ 2(x+4)=2(0+4)=8 - this is ten digit.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

h/o/e/s mad

step-by-step explanation:

si si si