Mathematics, 09.10.2019 00:30 iiMxlissaii
If f(x)=4x-1 and g(x)=x^2+7, what is g(f(x))
Answers: 1
![\bf \begin{cases} f(x)=4x-1\\ g(x)=x^2+7 \end{cases}~\hspace{7em}g(~~~f(x)~~~)=[~f(x)~]^2+7 \\\\\\ g(~~~f(x)~~~)=[~4x-1~]^2+7\implies g(~~~f(x)~~~)=(4x-1)(4x-1)+7 \\\\\\ g(~~~f(x)~~~)=\stackrel{\mathbb{F ~O~ I~ L}}{(16x^2-8x+1)}+7\implies g(~~~f(x)~~~)=16x^2-8x+8](/tpl/images/0301/8905/619a4.png)
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If f(x)=4x-1 and g(x)=x^2+7, what is g(f(x))...
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