Sophia and tyler are running around a 400-meter track. they start running from the same place, at the same time. sophia runs at a speed of 5 m/s and tyler runs at a speed of 4 m/s. how long will it take sophia to lap tyler?

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The answer is: There will take 400 seconds to Sophia to lap Tyler.

To solve this problem we need to write equations in function to Tyler's distance when Sophia laps him, so:

Let be "x" the position of Tyler when Sophia is 400 m ahead of him.

Let be "x+400" the position of Sophia when she laps Tyler

Also, we must remember that time is equal to:

So, the equation to calculate the position of the Tyler when Shopia laps him, can be written like this:

Then,

Therefore, the distance that Tyler's ridden when Sophia laps him is 1600m.

Let's calculate the time with the following formula:

If we want to prove that the result is ok, let's substitutite the same distance in the Sophia's distance equation:

Hence,

There will take 400 seconds to Sophia to lap Tyler.

Have a nice day!

175

step-by-step explanation:

2 inches x 10 miles = 200 miles - 3 inches = 175

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v