1. given 4x – 8y = 8:
a. transform the equation into slope-intercept form.
b. find the slope and y-intercept of the line.
c. find the equation, in point-slope form, of the line that is perpendicular to this line and passes through the point (1, 2

A.) 4x-8y=8 move the x over to the other side
     -8y=-4x+8 divide everything by -8.
     y=1/2x-1    
b.) In slope-intercept form, it has a form of y=mx+b where m is the slope, and b is the y-intercept. So, the slope is 1/2, and the y-intercept is (0,-1).
c.) First, if you see the word perpendicular to this line, you will need to negative reciprocate the slope. Which means you flip the fraction and add a negative sign (or remove if there is one existing). The form of point-slope is y-y1=m(x-x1) and since the slope is 1/2 in the original, the perpendicular one would be y-2=-2(x-1) if you need slope intercept form it can simplify to y-2=-2x+2, then add two to both sides to make it y=-2x+4.