At an amusement park, the probability that a child eats a hot dog and drinks a soda pop is 0.47. the probability that a child eats a hot dog is 0.69 and the probability that a child drinks soda pop is 0.86. what is the probability (rounded to the nearest hundredth) that a child drinks soda pop given that the child has already eaten a hot dog?

hint: p(a|b)=p(a∩b) / p(b)

0.55

0.40

0.32

0.68

option D

0.68

Step-by-step explanation:

Conditional Probability:

Finding the probability of an event given that something else has already happened.

p(A) =  The probability that a child eats a hot dog  = 0.69

p(B) =  The probability that a child drinks soda pop = 0.86

p(A∩B) = The probability that a child eats a hot dog and drinks a soda pop = 0.47

Formula to use

P(A|B) = P(A∩B) / P(A)

          = 0.47 / 0.69

          = 0.68

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

< 3

step-by-step explanation:

c

c

c

c

c

c

c

cc

c

step-by-step explanation: