Aset of normally distributed data has a mean of 3.2 and a standard deviation of 0.7. find the probability of randomly selecting 30 values and getting a mean greater than 3.6.

Step-by-step explanation:

A set of normally distributed data has a mean of 3.2 and a standard deviation of 0.7. Find the probability of randomly selecting 30 values and obtaining an average greater than 3.6.

We can denote the population mean with the symbol

According to the information given, the data have a population mean:

.

The standard deviation of the data is:

.

Then, from the data, a sample of size is taken.

We want to obtain the probability that the sample mean is greater than 3.6

If we call

to the sample mean then, we seek to find:

To find this probability we find the Z statistic.

Where:

Where is the standard deviation of the sample

Then:

The probability sought is:

When looking in the standard normal probability tables for right tail we obtain:

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m

step-by-step explanation: