The chs baseball team was on the field and the batter popped the ball up. the equation b(x)=80t-16t^2+3.5 represents the height of the ball above the ground in feet as a function of time in seconds. how long will the catcher have to get in position to catch the ball before it hits the ground? round to the nearest second.

t = 5 seconds

Step-by-step explanation:

We must solve the equation of movement of the ball as a function of time in seconds.

We must find how many seconds it takes until the ball touches the ground. When the ball touches the ground, the height b (t) = 0

Then we equate the equation to zero and solve for t.

Use the quadratic formula.

Where

We take the positive solution

t = 5 seconds

1.0

step-by-step explanation:

sorry i need the points

step-by-step explanation:

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