Given circle assume that ab is tangent to the circle and ad passes through the center of the circle. if the circle has a radius of 5cm and ab is 6cm what is the length of the secant

d. 2√34 cm

Step-by-step explanation:

Secant BD is the hypotenuse of right triangle ABD with legs given as AB = 6 cm and AD = 10 cm. Hence the Pythagorean theorem can be used to find BD:

BD = √(AB² +AD²) = √((6 cm)² +(10 cm)² = √136 cm = 2√34 cm

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

solve systems of equations by graphing. a system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. the solution of such a system is the ordered pair that is a solution to both equations. to solve a system of linear equations graphically we graph both equations in the same coordinate system