What is the area of a right triangle with vertices of (-2,-,-4), and (2,5)?

A = 18

Step-by-step explanation:

The formula for the area of a triangle is  

A = ½bh

b = x₂ - x₁ = 2 - (-2) = 2 + 2 = 4

h = y₂ - y₁ = 5 - (-4) = 5 + 4 = 9

A = ½ × 4 × 9 = 18

The area of the triangle is 18.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)