1) given: circle k(o), ed= diameter ,m∠oef=32°, m(arc)ef=(2x+10)° find: x
2)given: circle k(o), m(arc) fe=56°, fd=ed find: m∠efo, m∠efd

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is , so the measure of arc DF is

The inscribed angle theorem tells us that the central angle subtended by arc DF, , has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

so the measure of arc DF is also 64 degrees. So we have

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2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation:

the correct option is b

step-by-step explanation: